Find the zeroes -12x^2+96-6x^3+x^4+56x

Mathematics

1 answer:

Alla [95]3 years ago

7 0

Your roots would be 6, 4, and -2

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$3 \frac{1}{2} r = 28 \\ \frac{7}{2} r = 28 \\ \frac{ \frac{7}{2} }{ \frac{7}{2} } r = \frac{28}{ \frac{7}{2} } \\ r = \frac{ \frac{56}{2} }{ \frac{7}{2} } \\ r= \frac{56}{7}$

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42 + 8x + 13 = 7

8x + 55 = 7

8x = 7 - 55 subtract both sides by 55

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