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Usimov [2.4K]
4 years ago
11

What is the value of x

Mathematics
1 answer:
marta [7]4 years ago
5 0

Answer:

The answer would be Option 3: 43.25

Step-by-step explanation:

Triangles angles all added together add up to 180 degrees.

So first we subtract 93.5 from 180. This gives us 86.5. The we divide this by 2 to get 43.25.

Hope this helped!

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The sine of 67 degrees is 0.92. what is the cosine of 23 degrees?
patriot [66]

Answer:

Cos23° is -0.532833...........

7 0
3 years ago
Read 2 more answers
First chance you get the best marks ​
garri49 [273]

Answer:

<h2><em><u>First box and last box.</u></em></h2>

Step-by-step explanation:

<h2><em><u>It is the first box.</u></em></h2>

Distribute 7 to the first number

7 * -3/4 = -21/4

-21/4 = 5  -1/4

Distribute 7 to the second number

7 * -3

= -21

Put the numbers together

<h2><em><u>5  -1/4x  -21 is the answer.</u></em></h2>

<h2><em><u>It is also the last box.</u></em></h2>

They separated the parenthesis.

So it is still 7 * -3/4

and

7*-3.

Hope this helps,

Kavitha

7 0
4 years ago
Which expression represents:<br> the sum of a number and 12<br> N 12<br> 1 x 12<br> 12 m<br> 12
marysya [2.9K]
Sum is the result of adding so
12 + x, but i don't see it as a option.
7 0
3 years ago
Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc
Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when M = 0.3, \sigma = 4.103. So

M = z*\frac{\sigma}{\sqrt{n}}

0.3 = 1.96*\frac{4.103}{\sqrt{n}}

0.3\sqrt{n} = 1.96*4.103

\sqrt{n} = \frac{1.96*4.103}{0.3}

(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}

n = 718.57

Rouding up

We need a sample size of at least 719

6 0
3 years ago
Given:AB=12 AC=6 prove:C is the midpoint of AB
alisha [4.7K]

since AC=1/2AB=6 THEREFORE C is the midpoint ofAB

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