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anygoal [31]
3 years ago
6

Which exponential function models the data? Round

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
6 0

Answer:

f(x) = 401.19(1.08)x

Step-by-step explanation:

ryzh [129]3 years ago
4 0

Answer:

the answer is f(x) = 401.19(1.08)x

Step-by-step explanation:

use a regression calculator.

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Could someone explain why (-4)² is equal to 16 but -4² is equal to -16​
erica [24]

Answer:

It's all about the brackets.

Step-by-step explanation:

If we do (-4)^2, the brackets make it -4 x -4 and the two negatives make a positive of 16.

If we do -4^2, that means that the 4 is squared before putting the minus sign there so you have 4x4 = 16 then put the minus to get -16.

Hope this helps!

treviglaslibrary

8 0
3 years ago
Read 2 more answers
The expression 50w+400 represents the amount of money Jenny has in her savings account after an unknown number of weeks. How muc
Sloan [31]

She originally had $400 in her bank account.

The 50w represents the amount she will put away each week.

3 0
3 years ago
Radical expression of 7 x 2 / 3
TiliK225 [7]
I think it going to be 21/2 or 10 1/2
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3 years ago
What does tempature measure
Hoochie [10]

Answer:

Temperature is a measure of the average kinetic energy of the particles in an object.

Step-by-step explanation:

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6 0
3 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
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