The answer to the question I believe is C
Answer:
y-determinant = 2
Step-by-step explanation:
Given the following system of equation:
Let's represent it using a matrix:
![\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C1%26-3%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
![\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C1%267%5Cend%7Barray%7D%5Cright%5D%20)
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2
Answer:
6. SAS Postulate
5. ASA Postulate
Step-by-step explanation:
Answer:
Tangent line states that a line in the plane of a circle that intersect the circle in exactly one point.
Common external tangent states that a common tangent that does not intersects the line segment joining the centers of circle.
Common internal tangent states that a common tangent that intersects the line segment joining the centers of circle.
Circumscribe polygon states that a polygon with all sides tangent to a circle contained within the polygon.
Therefore:
A polygon with all sides tangent to a circle contained within the polygon = Circumscribe polygon
A common tangent that intersects the line segment joining the centers of circle = Common internal tangent
A common tangent that does not intersects the line segment joining the centers of circle = Common external tangent
a line in the plane of a circle that intersect the circle in exactly one point = Tangent line
Answer:
The correct option is d. 0.60
Step-by-step explanation:
Consider the provided information.
At Mike’s favorite coffee shop, the coffee of the day is either a dark roast, a medium roast, or a light roast.
The coffee being a light roast is 0.15 and the probability of the coffee being a dark roast is 0.25.
Pr(Light roast) = 0.15
Pr(Dark roast) = 0.25
We need to find the probability of the coffee of the day not being a light roast or a dark roast on the next day that Mike visits the coffee shop.




Hence, the correct option is d. 0.60