Answer:
16.36%
dependent
Step-by-step explanation:
If we choose a crayon, then another crayon without putting the first one back in the supplies box, that means the event is dependent. The keyword to find whether some events dependent is " without putting back" because that means the first pick will reduce the number of crayons pool for the second pick.
There are 3 + 2 + 6 = 11 total crayons. There are 6 blue and 3 red crayons. The probability for picking blue then red crayon will be:
6/11 * 3/10 = 18/110= 0.163636 = 16.36%
Answer:
f=110132.328974hti
Step-by-step explanation:
Let's try to divide the sentence into multiple parts and then combine it one by one to make it easier to understand.
1. True
2 times y and 6 -------->(2y+6)
the square of the sum of "2 times y and 6" -------->(2y+6)^2
8 times "the square of the sum of 2 times y and 6"------> 8(2y+6)^2
2. True
the difference of x and 7 -------->(x-7)
9 and x -------->(9 + x)
2 times the product of the sum of
"9 and x" and "the difference of x and 7"-------> 2(9 + x) (x-7)
3. True
difference of 5 times x and 3 -------->(5x-3)
the square of the difference of 5 times x and 3------->(5x-3)^2
4. False
The description should be: the product of 7 and the square of x
the product of 7 and x -------->(7x)
the square of the product of 7 and x -------->(7x)^2
5. True
This one should be clear as it was one sentences
the sum of y squared(y^2) and three times y(3y) minus 4-------->y^2+ 3y -4
6. False
The description should be: the product of 5 and 8 times the square of x plus the sum of 20x and 8
the sum of 20x and 8 -------->20x+8
8 plus the square of x plus the sum of 20x and 8-------->8+ x^2 +20x+8
the product of 5 and.... ------->(5)(........
the product of 5 and
8 plus the square of x plus the sum of 20x and 8---->(5)(8+ x^2 +20x+8)
3/6 so 1/2 litre …….. (dots are for the 20 character limit)
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The given graph is symmetric along Theta = 0
[ polar axis ]
Because it's a horizontal line that divides the features on the graph into two equal halves. and there's no other suitable symmetric relation.
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
