Answer:
4
Step-by-step explanation:
Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:

What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So



has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79
Answer:
512 is equivalent
Step-by-step explanation:
2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2=2^9
2^9=512
15.
6 pachages
each pcage has 30
6*30=180 total
17 left over
how many used
used=total-left over
used=180-17
used=163
16. xy is 2 digit number
multiplules of 10 (whole multipules) always end with 0 so y=0
and has 3 as one of its factors
factors of 3 is 3,6,9,12
30,60,90 is answer
17.
30 in 9 parks
30 times 9
30=10 times 3
3*10*9
group the 3 and 9
10*(3*9)
3*9=27
10*(27)
270
15. 163
16. 30,60,90
17. see above, 270