36 and 100 are both perfect squares
the factorization of x^2-y^2 is (x+y)(x-y)
substitute x^2 with 36x^2 and y^2 with 100y^2:
<span>36x^2-100y^2=
(6x+10y)(6x-10y) or
4(3x+5y)(3x-5y)</span>
Hi,
(4x−2)(3x^2−2x+1)
=(4x+−2)(3x^2+−2x+1)
=(4x)(3x2)+(4x)(−2x)+(4x)(1)+(−2)(3x2)+(−2)(−2x)+(−2)(1)
=12x3−8x^2+4x−6x^2+4x−2
=12x3−14x2+8x−2
Have a great day!
Answer:
b
Step-by-step explanation:
Answer:
n=30
Step-by-step explanation:
Multiply all terms by the same value to eliminate fraction denominators
Cancel multiplied terms that are in the denominator
Re-order terms so constants are on the left - you end up with n=30
Answer:
2
Step-by-step explanation:
