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Norma-Jean [14]
3 years ago
5

The mean of 9, 6, 5, 64, 7, 4, 2

Mathematics
2 answers:
Georgia [21]3 years ago
4 0

Answer:

The mean is 11.25

Step-by-step explanation:

to get the mean youll first add all the numbers together and divide them by the amount of numbers that you have then you get your avarage. Once you have your avarage then you subtract it from all your numbers , add up what you get and divide again by the amont of numbers you have

swat323 years ago
4 0
The mean of this number is 11.45
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A rectangular prism is shown below. What is the surface area, in square centimeters?
Orlov [11]

Answer:

174 square centimetres

Step-by-step explanation:

The formula for finding the surface area of a rectangular prism is

SA = 2LW + 2LH + 2HW

Therefore surface area will be

= 2(11*5) + 2(11*2) +2(2*5)

= 2 * 55 + 2 * 22 + 2 * 10

= (110 + 44 + 20) square cm

Which gives you 174 square centimetres.

3 0
3 years ago
17) Convert the number to scientific notation 0.00317
Masteriza [31]

Answer:

3.17x10^-3

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  

10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

6 0
3 years ago
Can you tern this into a equation
Aleks [24]

Answer:

n + p x 3 = t

Step-by-step explanation:

n= Navita's money

p= Pawan's money

t= total money

8 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
0.729 rounded by the nearest tenth
katrin [286]
0.7 is rounded to the tenth place
4 0
3 years ago
Read 2 more answers
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