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erastova [34]
3 years ago
6

Let X and Y be joint continuous random variables with joint density function fpx, yq " # e ´y y 0 ă x ă y, 0 ă y ă 8 0 otherwise

Compute ErX2 | Y " ys. Hint: Start with ErX2 | Y " ys " ż y 0 x 2 fX|Y px |
Mathematics
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

For X, the parameter

is λX = 1/2 and for Y it is λY = 1. Using the formula sheet, Mean is

E[Z] = E[X] + 2E[Y ] = 4. Variance is V ar(Z) = V ar(X) + 4V ar(Y ) = 8.

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Step-by-step explanation:

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3 years ago
An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan
AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=x_{0}]

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I hope it helps!

6 0
3 years ago
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Gala2k [10]

Answer:

2 7/8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
the sum of three times one number, x, and five times a second number,y, is 77. if the sum of the two numbers is 19, find the two
HACTEHA [7]

Answer:

x=9, y=10. (9, 10). The two numbers are 9 and 10.

Step-by-step explanation:

3x+5y=77

x+y=19

------------------

3x+5y=77

-3(x+y)=-3(19)

---------------------

3x+5y=77

-3x-3y=-57

-------------------

2y=20

y=20/2

y=10

x+10=19

x=19-10

x=9

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3 years ago
Write an expression that can be used to solve the problem.
Ymorist [56]
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3 years ago
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