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stiks02 [169]
3 years ago
13

I need the answers please help

Mathematics
1 answer:
Andrej [43]3 years ago
4 0

Answer:

For the first one: 2+3(1) = 5

Second one: 5=5

Third one: 1 = -2 + 3

Last one: 1=1

Step-by-step explanation:

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ok

Step-by-step explanation:

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Please help! Correct answer only, please! Consider the following table. A movie theatre is planning to increase each of their va
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<u>Step-by-step explanation:</u>

In order to increase each ticket by $2, you are ADDING 2 to each value.

So you create a matrix of all 2's and add that to the given matrix.

\left[\begin{array}{cc}2&2\\2&2\\2&2\end{array}\right] +\left[\begin{array}{cc}8&10\\12&16\\6&8\end{array}\right]\quad =\quad \large \left[\begin{array}{cc}10&12\\14&18\\8&10\end{array}\right]

7 0
3 years ago
Remember to show work and explain. Use the math font.
vichka [17]

Answer:

\large\boxed{1.\ f^{-1}(x)=\sqrt[12]{3^x}}\\\\\boxed{2.\ f^{-1}(x)=\sqrt[4]{3^x}}\\\\\ \boxed{3.\ f^{-1}(x)=\sqrt[3]{4^{7-x}}}

Step-by-step explanation:

(a^n)^m=a^{nm}\\\\\log_ab=c\iff a^c=b\\\\a^{\log_ax}=x\\\\n\log_ab=\log_ab^n\\\\\log_ab+\log_ac=\log_a(bc)\\============================\\\\1.\\y=3\log_3x^4\to y=\log_3(x^4)^3\to y=\log_3x^{12}

2.\\y=\log_3x^4\\\\\text{Exchange x and y. Solve for y:}\\\\\log_3y^4=x\Rightarrow3^{\log_3y^4}=3^x\Rightarrow y^{4}=3^x\\\\y=\sqrt[4]{3^x}\\-------------------------

3.\\y=-\log_4x^3+7\\\\\text{Exchange x and y. Solve for y:}\\\\-\log_4y^3+7=x\qquad\text{subtract 7 from both sides}\\\\-\log_4 y^3=x-7\qquad\text{change the signs}\\\\\log_4y^3=7-x\Rightarrow4^{\log_4y^3}=4^{7-x}\\\\y^3=4^{7-x}\Rightarrow y=\sqrt[3]{4^{7-x}}

7 0
3 years ago
Can someone please help me​
Svetllana [295]

Step-by-step explanation:

I think its 2/6 becuase its bigger

3 0
3 years ago
Read 2 more answers
For the function y = 4x – 2, what is the value of the function when x is equal to -3?
Nesterboy [21]

Answer:

y = 4 (-3) - 2

y = -12 - 2

y = -14

Step-by-step explanation:

4 0
3 years ago
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