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iragen [17]
3 years ago
15

Name the legs of abc

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0
It looks as if "B" is the right angle so
AC is the hypotenuse
AB and BC are the legs


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Simplify ( 8∙4∙2 8∙7 )^2 × ( 8 0 7−3 )^3 × 7 −9 .
stich3 [128]

\bf ~\hspace{7em}\textit{negative exponents}
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a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
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\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
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\rule{34em}{0.25pt}\\\\
\left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2\times \left( \cfrac{8^0}{7^{-3}} \right)^3\times 7^{-9}\implies \left( \cfrac{8\cdot 8}{8\cdot 7} \right)^2\times \left( \cfrac{1\cdot 7^3}{1} \right)^3\times \cfrac{1}{7^9}


\bf \left( \cfrac{8}{8}\cdot \cfrac{8}{7} \right)^2\times (7^3)^3\times \cfrac{1}{7^9}\implies \left( \cfrac{8}{7} \right)^2\times 7^{3\cdot 3}\times \cfrac{1}{7^9}\implies \cfrac{8^2}{7^2}\times \cfrac{7^9}{7^9}
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3 years ago
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jasenka [17]

Answer:

B: 11 minutes.

Step-by-step explanation:

So, we know that the machine prints at a constant rate.

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We can write an equation. If t represent the number of minutes and p represent the amount of posters, then:

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We want to know how long it will take Jeffrey to make 396 posters.

So, we can substitute 396 for p and solve for t. Hence:

396=36t

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t=11

Therefore, it will take Jeffrey 11 minutes to make 396 posters.

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3 years ago
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The best and the most correct answer among the choices provided by the question is the first choice. The pair of angles that are vertical is <span>∠KRC and ∠CRH ∠MRC and ∠KRM ∠ERT. </span>I hope my answer has come to your help. God bless and have a nice day ahead!
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The marked price of an article is 25% above its cost price when it is sold at a discount of 15%
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