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MatroZZZ [7]
3 years ago
13

Event A has a 0.3 probability of occuring and event B has a 0.4 probability of occuring. A and B are independent events. What is

the probability that either A or B occurs?
0.42

0.54

0.70

0.12
Mathematics
2 answers:
GarryVolchara [31]3 years ago
4 0
When you say either, you add both A and B
0.3+0.4=0.7
Your answer is 0.70 which means 70%
Varvara68 [4.7K]3 years ago
3 0

Answer:

The probability that either A or B occurs is 0.58

Step-by-step explanation:

P(A) = 0.3

P(B) =0.4

Since we are given that A and B are independent events

So, P(A∩B)=P(A)*P(B)

P(A∩B)=0.3*0.4=0.12

So, P(A∪B)= P(A)+P(B)-P(A∩B)

P(A∪B)= 0.3+0.4-0.12

P(A∪B)=0.7-0.12

P(A∪B)=0.58

Now, the probability  that either A or B occurs (or both occurs) = P(A∪B)+P(A∩B)

= 0.58

Thus,the probability that either A or B occurs is 0.58

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Vadim26 [7]

we know that

The angle bisector, is the line or line segment that divides the angle into two equal parts.

So

in this problem

m∠ZXW=m∠WXY+m∠ZXY

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<u>the answer part a)</u>

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