Event A has a 0.3 probability of occuring and event B has a 0.4 probability of occuring. A and B are independent events. What is
the probability that either A or B occurs?
0.42
0.54
0.70
0.12
2 answers:
When you say either, you add both A and B
0.3+0.4=0.7
Your answer is 0.70 which means 70%
Answer:
The probability that either A or B occurs is 0.58
Step-by-step explanation:
P(A) = 0.3
P(B) =0.4
Since we are given that A and B are independent events
So, P(A∩B)=P(A)*P(B)
P(A∩B)=0.3*0.4=0.12
So, P(A∪B)= P(A)+P(B)-P(A∩B)
P(A∪B)= 0.3+0.4-0.12
P(A∪B)=0.7-0.12
P(A∪B)=0.58
Now, the probability that either A or B occurs (or both occurs) = P(A∪B)+P(A∩B)
= 0.58
Thus,the probability that either A or B occurs is 0.58
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