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puteri [66]
3 years ago
15

What is the first step needed to solve 3 over 4 the whole multiplied by x minus 3 equal negative 18? Add 3 to both sides Subtrac

t 18 from both sides Multiply both sides by 3 Divide both sides by 4
Mathematics
2 answers:
malfutka [58]3 years ago
6 0
The most logical answer would have to be to add 3 to both sides of the equation 
MatroZZZ [7]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Add 3 to both sides.

You might be interested in
Select from the following choices those graphs that represent only a dilation applied to this polygon with a scale factor great
romanna [79]

Answer:

B and C

Step-by-step explanation:

Required

Select graphs that are dilated by a scale factor greater than 1

For graph A:

Graph A is smaller than the original graph. This indicates dilation with a scale factor less than 1

For graph B:

Graph B is bigger than the original graph and is dilated over (0,0). This indicates dilation with a scale factor greater than 1

For graph C:

Graph C is bigger than the original graph; however, it is not dilated over (0,0). This indicates dilation with a scale factor greater than 1

For graph D:

Graph D is bigger than the original graph; however, it is not only dilated but also flipped over (i.e. rotated).

<em>Hence, b and c is true</em>

5 0
3 years ago
the height of a house having three rooms of the dimensional 9 feet into 12 feet 14 feet into 16 feet and 12 feet into 14 feet re
Semmy [17]

Answer:

Amount required = 2,217,600

Step-by-step explanation:

Dimensions of the rooms are as follows;

Room 1; 9 feet × 12 feet

Room 2; 14 ft × 16 ft

Room 3; 12 ft × 14 ft

Perimeter of rooms;

P1 = 2(9 + 12) = 42 ft

P2 = 2(14 + 16) = 60 ft

P3 = 2(12 + 14) = 52 ft

Total perimeter; P = 42 + 60 + 52 = 154 ft

Height is 90 ft.

Thus, total area is;

A = 154 × 90

A = 13860 ft²

Rate of painting is 160 per Sq.ft.

Thus amount to paint entire area = 160 × 13860 = 2217600

4 0
3 years ago
Describe the graph of the function. y = |x – 4| – 7
Lemur [1.5K]

Answer:

This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:

(x-4)=0 ===> x=4,

so that now you have to plot 2 functions!

For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:

|x-4| = -(x-4)=4-x

Then:

for x<=4, y = -x+4-7 = -x-3

for x=>4, (x-4) is positive, so no changes:

y= x-4-7 = x-11,

Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11

In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:

x=4 and x= 3 for y=-x-3

And just x=5 for y=x-11

The reason is that the absolute value is continuous, so x=4 works for both:

x=4===> y=-4-3 = -7

x==4 ====> y = 4-11=-7!

abs() usually have a cusp int he point where it is =0

Step-by-step explanation:

5 0
3 years ago
Thank you so much for you help​
ankoles [38]
Your welcome for the help
8 0
3 years ago
Share £15 in 2:3 <br> Please help me put
son4ous [18]
2 ratio 3,so, 2+3=5
15/5=3 add and then division
5 0
4 years ago
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