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mylen [45]
2 years ago
8

Equação de 1°grau resultado-2x+3=-1+x+2​

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
8 0

Answer:

2/3

Step-by-step explanation:

-2x+3=-1+x+2

-2x-x+3=-1+2

-3x+3=1

-3x=1-3

-3x=-2

3x=2

x=2/3

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Solve the inequality 2x>30+5/4x
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Answer:

Step-by-step explanation:

2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} }  \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0

x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

case~2

if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

8 0
1 year ago
5(17+13) ÷(8-7) <br> Simply the expression
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First expand by multiplying
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Then 5 x 13= 65
As them
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3 years ago
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3 years ago
Prove the polynomial identity.
Ronch [10]

Answer:

The answer to your question is: 2, 4, 5, 1 , 3

Step-by-step explanation:

The first line is the second

                                             (3x² - 6)² - (3x²)² = 36(1 - x)(1 + 1)

The second line is the forth

                                             9x⁴ - 36x² + 36x² - 9x⁴ = 36(1 - x)(1 + x)

The next line is the fifth

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The next line is the first

                                             36(1 - x²) = 36(1 - x)(1 + x)

The last line is the third

                                             36(1 - x)(1 + x) = 36(1 - x)(1 + x)

3 0
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