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Angelina_Jolie [31]
3 years ago
11

Let abcd be a square piece of paper. A is folded into c and the b is folded into d. the area of the resulting figure is 9 square

inches. Find the perimeter of square ABCD
A.9
B.16
C.18
D.24
E.36
Mathematics
1 answer:
neonofarm [45]3 years ago
4 0
9 is the correct answer
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2<br> Multiple choice. How many solutions does the equation 6 + 1 = -6x+ 10 have?
natulia [17]

Answer:

x = 0.5, one solution

Step-by-step explanation:

6+1 = -6x + 10

7 = -6x + 10

-3 = -6x

6x = 3

x = 3/6

x = 1/2

x = 0.5

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3 years ago
Find the measure of side a
matrenka [14]

Answer:

8.22899353m

= 8m(round)

Step-by-step explanation:

14 * sin(36 degree) = 8.22899353

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What is the common difference in this sequence: 5, 17, 29, 41, 53?
irina1246 [14]
The common difference is 12.
5 0
3 years ago
Read 2 more answers
One morning, John drive 5 hours before stopping to eat. After lunch, he. increased his speed by 10 mph. If he completed a 500-mi
Marrrta [24]
So  he drove 5hrs, before lunch, now, he was going at speed, say "r", after he ate, he sped up by 10mph, so, his rate is whatever "r" is, plus 10, or " r + 10 ", after lunch

we know the whole trip took 10hrs, so, is 5hrs before lunch and 5hrs after lunch

we also know the whole trip was 500miles, so if he drove, say "d" miles before lunch, after lunch he drove the slack after lunch, or " 200 - d "

recall, your d = rt, distance = rate * time

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;\textit{before lunch}&d&r&5\\&#10;\textit{after lunch}&500-d&r+10&5&#10;\end{array}&#10;\\\\\\&#10;&#10;\begin{cases}&#10;\boxed{d}=5r\\&#10;500-d=(r+10)5\\&#10;----------\\&#10;500-\boxed{5r}=(r+10)5&#10;\end{cases}&#10;\\\\\\&#10;\cfrac{500-5r}{5}=r+10\implies 100-r=r+10

and I'm sure you know what that is
6 0
3 years ago
What are the center and radius f the circle with equation xthe power of 2 +y power of 2 -4x -6y +8=0
Dovator [93]
<span>x² +y² -4x -6y +8=0
(x² -4x) +(y² -6y) = -8
We are going to complete square for x and y,
it should look like a²+2ab+b² = (a +b)², or </span>a²-2ab+b² = (a -b)²,
<span>
(x²-2*2x+2²) -2² + (y²-2*3y +3²)-3²=- 8
(x-2)²+(y-3)²-4-9=-8
</span>(x-2)²+(y-3)²=-8+13
(x-2)²+(y-3)²=5
<span>
Formula a circle (x-h)²+(y-k)²=R², where vertex has coordinates (h, k) 

So , for our circle  vertex (2,3) and radius = </span>√5<span>


</span>
6 0
3 years ago
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