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Mademuasel [1]
3 years ago
6

Which statement best shows the difference between a line and a point

Mathematics
1 answer:
Vlada [557]3 years ago
7 0
A point denotes a location or a specific designation in space. A point has no measurements, it is simply a dot in one dimension. A line is composed of infinitely many points which extends in two opposite sides, the positive and negative infinities. A line is also one dimensional. If it were a segment, it would have two opposite endpoints, not extending to both infinities. 
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If there are 21 picks, 6 are orange
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Which of the following equations shows how substitution can be used to solve
maxonik [38]

Answer:  Choice B)

2x+5(2x+3) = 3

============================================

Reasoning:

We start with the second equation 2x+5y = 3

Since y = 2x+3 from the first equation, we can replace every copy of y with (2x+3). This replacement is valid because y and 2x+3 are the same.

So that's how we go from 2x+5y = 3 to 2x+5(2x+3) = 3

This replacement is done to get rid of the y variable, and it allows us to solve for x later on.

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3 years ago
Find an equation of the line that passes through the point (4, 3) and is perpendicular to the line 2x + 9y − 6 = 0.
vesna_86 [32]
Perpendicular has the reciprocal slope and u have to put the point given into point slope.

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3 0
3 years ago
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

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Take the length of the larger divide it by the smaller

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