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SIZIF [17.4K]
2 years ago
5

The graph of an exponential function passes through (1, 10) and (4, 80). Find the function that describes the graph.

Mathematics
2 answers:
Otrada [13]2 years ago
7 0

Answer:

y=5 \cdot 2^x

Step-by-step explanation:

An exponential function is written in the form:

  • y=ab^x

We can use the given points that the exponential function passes through to solve for a and b.

Create a system of equations by substituting <u>(1, 10)</u> and <u>(4, 80)</u> into the exponential form of a function.

  • \text{I}:\ 10=ab^1
  • \text{II}: \ 8 0=ab^4

Divide Equation I by Equation II in order to cancel out variable a.

  • \displaystyle \frac{80=ab^4}{10=ab}
  • 8=b^3
  • b=2

Now we can solve for a by substituting b back into either equation from the system of equations.

  • 10=ab
  • 10=a(2)
  • a=5

Substitute 5 for a and 2 for b into the form of an exponential function to find the exponential function that passes through (1, 10) and (4, 80).

  • y=5 \cdot 2^x

y = 5 · 2ˣ is the exponential function that describes the graph.

svetlana [45]2 years ago
4 0

Answer:

  • y = 5*2ˣ

Step-by-step explanation:

<u>Exponential function:</u>

  • y = abˣ

<u>Ordered pairs given:</u>

  • (1, 10) and (4, 80)

<u>Substitute x and y values to get below system:</u>

  • 10 = ab
  • 80 = ab⁴

<u>Divide the second equation by the first one and solve for b:</u>

  • 80/10 = b³
  • b³ = 8
  • b = ∛8
  • b = 2

<u>Use the first equation and find the value of a:</u>

  • 10 = a*2
  • a = 5

<u>The function is:</u>

  • y = 5*2ˣ
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Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

43% of people have type O blood

This means that P(A) = 0.43

15% of people have Rh- factor

This means that P(B) = 0.15

52% of people have type O or Rh- factor.

This means that P(A \cup B) = 0.52

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

P(A \cap B) = P(A) + P(B) - P(A \cup B)

With what we have

P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

6 0
3 years ago
The angle Johnny holds his pen on paper creates a linear pair. The measure of one angle is 13x + 7. The
tresset_1 [31]
<h3>The value of x is 4.10</h3>

<em><u>Solution:</u></em>

Given that,

The angle Johnny holds his pen on paper creates a linear pair

Angles in a linear pair are supplementary angles

Two angles are supplementary, when they add up to 180 degrees

The measure of one angle is 13x + 7

The  measure of the second angle is one less than twice the first angle

Therefore,

Measure of second angle = twice the first angle - 1

Measure of second angle = 2(13x + 7) - 1

Measure of second angle = 26x + 14 - 1

Measure of second angle = 26x + 13

Therefore,

Measure of first angle + measure of second angle = 180

13x + 7 + 26x + 13 = 180

39x + 20 = 180

39x = 180 - 20

39x = 160

x = 4.1

Thus value of x is 4.10

3 0
3 years ago
What is the simplified form of the equation 4/5n - 3/5 = 1/5n?
Oksi-84 [34.3K]

Answer:

n = 1 if you meant "(4/5)n - (3/5) = (1/5)n"

Step-by-step explanation:                                                                              

There's some ambiguity here.  Did you mean (4/5)n or did you

              4

mean --------- ?  Please use parentheses to eliminate this ambiguity.

              5n    

I'm going to assume that you meant to type in (4/5)n - (3/5) = (1/5)n.

Then we have (3/5)n = 3/5, or n = 1

                                                                                                 

4 0
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