Question

A survey questioned 1000 people regarding raising the legal drinking age from 18 to 21. Of the 540 who favored raising the age, 390 were female. Of the 460 opposition responses, 130 were female. If a person selected at random from this group is a man, what is the probability that the person favors raising the drinking age?

Answer 1

Answer:

If a person selected at random from this group is a man, there is a 31.25% probability that the person favors raising the drinking age.

Step-by-step explanation:

We have these following informations:

There are 1000 people in total.

540 favored raising the age. Of them 390 were female, and 540-390 = 150 were male.

460 were opposed. Of them, 130 were female and 460-130 = 330 were males.

If a person selected at random from this group is a man, what is the probability that the person favors raising the drinking age?

There are 150+330 = 480 males. Of them, 150 favors raising the drinking age.

So

$P = \frac{150}{480} = 0.3125$

If a person selected at random from this group is a man, there is a 31.25% probability that the person favors raising the drinking age.