Answer:
or

Step-by-step explanation:
yz-plane has the equation
where
is a real constant. The normal vector of this plane (vector perpendicular to the plane) is

If the line is perpendicular to this plane, then it is parallel to the normal vector, so the equation of this line is

where
are coordinates of the point the line is passing through.
In your case, the line is passing through the point (0,0,8), so the canonical equation of the line is

Write a vector parametrization for this line

Answer:
Simplifying
(5n + -3) + -1(-2n + 7) = 0
Reorder the terms:
(-3 + 5n) + -1(-2n + 7) = 0
Remove parenthesis around (-3 + 5n)
-3 + 5n + -1(-2n + 7) = 0
Reorder the terms:
-3 + 5n + -1(7 + -2n) = 0
-3 + 5n + (7 * -1 + -2n * -1) = 0
-3 + 5n + (-7 + 2n) = 0
Reorder the terms:
-3 + -7 + 5n + 2n = 0
Combine like terms: -3 + -7 = -10
-10 + 5n + 2n = 0
Combine like terms: 5n + 2n = 7n
-10 + 7n = 0
Solving
-10 + 7n = 0
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '10' to each side of the equation.
-10 + 10 + 7n = 0 + 10
Combine like terms: -10 + 10 = 0
0 + 7n = 0 + 10
7n = 0 + 10
Combine like terms: 0 + 10 = 10
7n = 10
Divide each side by '7'.
n = 1.428571429
Simplifying
n = 1.428571429
Answer:
1. 40.00 sq units
2. 37.5 sq units
Step-by-step explanation:
1. Given slant height as 3 and the square base side as 4,
-The surface area of a right squared pyramid is calculated by summing the areas of the 4 triangles and the square base:

Hence, the area of the square pyramid is 40.00 sq units
2. The surface area of a cube is equivalent to 6 times the side of one face.
-Given the dimension of the sides as 2.5, surface area is obtained as:

Hence, the surface area of the cube is 37.5 sq units
Fifteen and sixty two thousanths
Answer:
length of the guy wire: 49.056
Step-by-step explanation:
here are the steps