Lagrange multipliers:
(if
)
(if
)
(if
)
In the first octant, we assume
, so we can ignore the caveats above. Now,
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
.
We also need to check the boundary of the region, i.e. the intersection of
with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force
, so the point we found is the only extremum.
Answer: c
Step-by-step explanation:
If the population triples every three hours, you would multiply three by the number of one hour to the power of three, making three hours. This function would triple it every three hours.
This is an exponential equation that can be represented by the following:
f(x) = a(b)^x
In this case...
25143 = a(0.66)^3
25143 is the population after 3 hours.
3 is the amount of time in hours.
0.66 represents the percent of the population remaining after each hour (66% as there is a 34% decline each hour).
We must solve for a, which is the initial population.
First, simplify (0.66)^3 to 0.2874.
25143 = 0.2874a
Now divide both sides by 0.2874 to isolate a.
a = 87455
There were initially 87,455 people within the city. I wouldn't want to be in that place!
180 is the area and the length is 1.25 so we need to find the width. We need to divide 180/1.25 which is 144.
144*1.25 is 180
The width is
144
Answer:
StartRoot 80 EndRoot
Step-by-step explanation:
|GH|² = (8 - 0)² + (1 - (-3))²
|GH|² = 64 + 16
|GH|² = 80
GH = sqrt(80)
