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ki77a [65]
3 years ago
10

What is the length of segment GH? On a coordinate plane, line G H has points (0, negative 3), (8, 1). StartRoot 48 EndRoot units

8 units StartRoot 80 EndRoot units 12 units
Mathematics
2 answers:
Mumz [18]3 years ago
7 0

Answer:

StartRoot 80 EndRoot

Step-by-step explanation:

|GH|² = (8 - 0)² + (1 - (-3))²

|GH|² = 64 + 16

|GH|² = 80

GH = sqrt(80)

Svetach [21]3 years ago
5 0

Answer:

C: StartRoot 80 EndRoot units

Step-by-step explanation:

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66 + 2bc – 46; b= 10, c=5
iren2701 [21]

Answer:

120

Step-by-step explanation:

66 + (2* 10*5)- 46

66+20×5−46

66+100−46

166−46

= 120

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3 0
2 years ago
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Last year Mr. Christian‘s class had 30 students .this year the number of students in his class is 150% of the number of students
kow [346]

Answer:

He has 45 kids now.

Step-by-step explanation:

3 0
2 years ago
Caden removed the label of a soup can like the one shown. What is the approximate area of the label if the can is 4 inches high
Dominik [7]

EXPLANATION

If the height of the can is 4 inches and the diameter is 3--> radius=1.5 inches, the area is given by the following relationhip:

\text{Area}_{\text{label}}=2\pi rh

Replacing terms:

\text{Area}_{\text{label}}=2\pi\cdot1.5\cdot4=12\pi=37.7in^2

The approximate area is 37.7 in^2

5 0
1 year ago
A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

V = s^2h = 5324

h = 5324 / s^2

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top s^2

Side area 4sh

Total surface area A = s^2 + 4sh

We can substitute h = 5324 / s^2

A = s^2 + 4s\frac{5324}{s^2}

A = s^2 + 21296/s

To find the minimum of this function, we can take the first derivative, and set it to 0

A' = 2s - 21296/s^2 = 0

2s = 21296/s^2

s^3 = 10648

s = \sqrt[3]{10648} = 22

h = 5324 / s^2 = 5324 / 22^2 = 11

4 0
3 years ago
Factor the expession using the gcf. 20p-60=
kotegsom [21]
That'd be 20(p-3).  Check by multiplying out 20(p-3)
5 0
3 years ago
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