<span>Cold fronts are marked on weather maps with the symbol of a blue line of triangles/spikes (pips) pointing in the direction of travel, and are placed at the leading edge of the cooler air mass. That cold/dense air wedges its way under the warm air out ahead of it.
</span><span>Warm fronts are marked on weather maps with a red line of half circles pointing in the direction of travel and mark the edge of an advancing warm air mass; a flow of warmer air that overtakes and replaces colder air. They are usually found on the east side of low-pressure storm systems. Since the cold air is denser than the warm air, the cold air hugs the ground. The lighter warm air slides up and over the cold air (called “overrunning”) and lacks any direct push on the cold air. Thus, the cold air is slow to retreat in the rapid advance of the warm air. This slowness of the cold air to retreat produces an atmospheric slope that is more gradual than the sharper slope that accompanies a cold front.
</span><span>Stationary fronts are depicted by alternating red half-circles and blue spikes (pips) pointing in opposite directions, indicating no significant movement. When neither air mass is replacing the other, the frontal boundary becomes more-or-less stationary; the opposing forces exerted by adjacent air masses of different densities are such that the frontal surface between them shows little or no movement (sometimes also referred to as a “quasi-stationary” front). In such cases, the surface winds tend to blow parallel to the frontal zone. The resultant weather is usually low cloud cover and long duration precipitation, and not much in the way of wind.
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i gave yu a little bit more info but read the stationary one
Answer:
Step-by-step explanation:
The three angles of a triangle always have to equal 180 in the end, so if you use the method which is the 4 in this instance, it is an obtuse angle that is equal to the top and left angle. You can add 1 and 2 to get 4, and do 4-3 to get 1+2, So, 4=1+2.
Answer:
Since Darcie wants to crochet a minimum of 3 blankets and she crochets at a rate of 1/5 blanket per day, we can determine how many days she will need to crochet a minimum of 3 blankets following the next steps:
- Finding the number of days needed to crochet one (1) blanket:
\begin{gathered}1=\frac{1}{5}Crochet(Day)\\Crochet(Day)=5*1=5\end{gathered}
1=
5
1
Crochet(Day)
Crochet(Day)=5∗1=5
So, she can crochet 1 blanket every 5 days.
- Finding the number of days needed to crochet three (3) blankets:
If she needs 5 days to crochet 1 blanket, to crochet 3 blankets she will need 15 days because:
\begin{gathered}DaysNeeded=\frac{NumberOfBlankets}{Rate}\\\\DaysNeeded=\frac{3}{\frac{1}{5}}=3*5=15\end{gathered}
DaysNeeded=
Rate
NumberOfBlankets
DaysNeeded=
5
1
3
=3∗5=15
- Writing the inequality
If she has 60 days to crochet a minimum of 3 blankets but she can complete it in 15 days, she can skip crocheting 45 days because:
AvailableDays=60-RequiredDaysAvailableDays=60−RequiredDays
AvailableDays=60-15=45DaysAvailableDays=60−15=45Days
So, the inequality will be:
s\leq 45s≤45
The inequality means that she can skip crocheting a maximum of 45 days since she needs 15 days to crochet a minimum of 3 blankets.
Have a nice day!
Answer:
x=2
Step-by-step explanation:
Solution is attached
You can plug 2 back into the equation to verify :)
Answer:

Step-by-step explanation:
The slope of a line passing through points
and
is:

Plugging in any two points in the table we have:
<u>First problem:</u>
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<u />
<u>Second problem:</u>
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