<span><span> Let ABC be an isosceles triangle with AB = AC. Let M denote the midpoint of BC (i.e., M is the point on BC for which MB = MC). Thena)<span> </span>Triangle ABM is congruent to triangle ACM.b)<span> </span>Angle ABC = Angle ACB (base angles are equal)c)<span> </span>Angle AMB = Angle AMC = right angle.d)<span> </span>Angle BAM = angle CAM
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Answer:
Step-by-step explanation:
equation of circle =
( h , k ) = center of origin
= radius
origin = ( 2 , -6 )
radius = 7
4÷631=157.75 hope that helps ya!!!!
3
multiply by 4
12
add 12
24
divide by 2
12
subtract 6
6
number 6 : 6(4) = 24... + 12 = 36...36/2 = 18.....- 6 = 12
number 8 : 8(4) = 32....+ 12 = 44...44/2 = 22....- 6 = 16
number 12: 12(4) = 48....+ 12 = 60...60/2 = 30....-6 = 24
well...by following these steps, it appears the original number doubles as a result.
