Answer:
9.45<em>g</em><em>=</em><em> </em>28.2
Divide through by 9.45
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>g</em><em>=</em><em>2</em><em>8</em><em>.</em><em>2</em><em>/</em><em>9</em><em>.</em><em>4</em><em>5</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>g=</em><em>2</em><em>.</em><em>9</em><em>8</em><em> </em><em>to </em><em>2</em><em>s</em><em>.</em><em>f</em>
Through 1-3 There should be a line that goes from (0,0) to (3,15) as they did work for three hours. The rest seems fine.
Well she has $10 and each spinach is $3 so she can not but no more than 3.
Given the table showing the distance Randy drove on one day of her vacation as follows:
![\begin{tabular} {|c|c|c|c|c|c|} Time (h)&1&2&3&4&5\\[1ex] Distance (mi)&55&110&165&220&275 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0ATime%20%28h%29%261%262%263%264%265%5C%5C%5B1ex%5D%0ADistance%20%28mi%29%2655%26110%26165%26220%26275%0A%5Cend%7Btabular%7D)
The rate at which she travels is given by

If Randy has driven for one more hour at the same rate, the number of hours she must have droven is 6 hrs and the total distance is given by
distance = 55 x 6 = 330 miles.
If the outliers are not included, what is the mean of the data? 76,79,80,82,50,78,83,79,81,82.
natta225 [31]
50 is the only outlier so take 50 out of the set then add the other 9 data points and divide by 9.<span>
76 + 79 + 80 + 82 + 78 + 83 + 79 + 81 + 82 = 720 / 9 = 80</span>