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nekit [7.7K]
2 years ago
5

The slope of the line below is -4. which of the following is the point-slope form of the line

Mathematics
1 answer:
MrMuchimi2 years ago
8 0

Answer:

y - b = -4(x - a)

Step-by-step explanation:

If the line passes through (a, b), then the point-slope form of the equation of the line is y - b = -4(x - a).   Where's the line you mention?

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Anyone know the area?
Elina [12.6K]
Answer:  The area of the triangle is:  " 8.5 cm² " ; 

                                         or, write as:  " 8\frac{1}{2} cm² " .
_______________________________________________________
Explanation:
_________________________________________________________
The formula {"equation"} for the area of a triangle is:

A = (\frac{1}{2}) * b * h ;
   
in which:  A = area; 
                 b = base;
                 h = [perpendicular] height;
___________________________________
{also, can be written as:  " A = (b * h) / 2 " .}.
______________________________________
Solve for the area, "A" ; by plugging in the known values shown in the figure (image attached):
______________________________________
                             base, "b" = 13 cm ;
[perpendicular] height, "h" =  5 cm ;
______________________________________
A = (b * h) / 2 ;

   = (13 cm * 5 cm) / 2 ; 

   = [ (13 * 5) cm²] / 2 ; 

    = 65 cm² / 2 ;

A  = " 8.5 cm² " ; or, write as:  " 8\frac{1}{2} cm² " .
_________________________________________________________
Answer:  " 8.5 cm² " ; or, write as:  " 8\frac{1}{2} cm² " .
_________________________________________________________
The area of the triangle is:  " 8.5 cm² " ; 

                         or, write as:  " 8\frac{1}{2} cm² " .
_________________________________________________________
5 0
3 years ago
In a computer program, distance due south from a point is treated as negative, and distance due north from a point is treated as
aleksandrvk [35]
The correct answer is -78.15 m.


Hope this helped! :)
7 0
3 years ago
Help Asap plz!!!! Thx Give 2<br>0 points
Arisa [49]

Answer:

(1,2) is a solution to both equations

Step-by-step explanation:

To determine if (1,2) is a solution to both equations, substitute into the equation and see if it is true

2x+y =4

2(1) + 2 =4

2+2 =4

4=4

true


y =3x-1

2 = 3(1) -1

2 =3-1

2=2

true

Since both statements are true

(1,2) is a solution to both equations

4 0
3 years ago
Chris is twice as old as Don, and next year the sum of their ages will be four times as much as Don’s age last year. Find their
RUDIKE [14]
Don's present age: 6
Chris's present age: 12
5 0
3 years ago
Write the slope-intercept form of the equation of each line given the slope and y-intercept.
saul85 [17]

Answer:

4b. −6x + y = −4

4a. 7x + 4y = −12

3b. y = ½x + 3

3a. y = −6x + 5

2b. y + 2 = −⅔(x + 3)

2a. y - 3 = ⅘(x - 5)

1b. y = -x + 5

1a. y = 5x - 3

Step-by-step explanation:

4.

Plug the coordinates into the Slope-Intercept Formula first, then convert to Standard Form [Ax + By = C]:

b.

2 = 6[1] + b

6

−4 = b

y = 6x - 4

-6x - 6x

_________

−6x + y = −4 >> Standard Equation

a.

4 = −7⁄4[-4] + b

7

−3 = b

y = −7⁄4x - 3

+7⁄4x +7⁄4x

____________

7⁄4x + y = −3 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]

4[7⁄4x + y = −3]

7x + 4y = −12 >> Standard Equation

__________________________________________________________

3.

Plug both coordinates into the Slope-Intercept Formula:

b.

5 = ½[4] + b

2

3 = b

y = ½x + 3 >> EXACT SAME EQUATION

a.

−1 = −6[1] + b

−6

5 = b

y = −6x + 5

* Parallel lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>].

__________________________________________________________

2.

b. y + 2 = −⅔(x + 3)

a. y - 3 = ⅘(x - 5)

According to the <em>Point-Slope Formula</em>, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

__________________________________________________________

1.

b. y = -x + 5

a. y = 5x - 3

Just write out the Slope-Intercept Formula as it is given to you.

I am joyous to assist you anytime.

3 0
3 years ago
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