It cost 199 for24 bottles of water what is the unit rate per bottle

Dion flips a coin 20 times and records if it comes up heads. if getting heads is a success, what is the probability of a success

hram777 [196]

The probability of a success on each roll of the coin that is filipped by Dion is 0.5.

<h3>What is the probability?</h3>

Probability is the likelihood that a stated event would occur. The odds the event occurs is 1 and the odds that the event does not happen is 0. If a coin is flipped, there is 50% chance of getting either a head or a tail.

To learn more about probability, please check: brainly.com/question/13234031

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4 0

2 years ago

Which values are solutions of the inequality 5 < y -8<br><br>8 , 9. , 13. , 15. , 20

Sladkaya [172]

Answer:

5 is greater than y-8 since 5 is positive it + in the begging +5 while - 8 is less than 0 because it has - in the begging

6 0

2 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

so

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago

Use multiplication to find 2 equivalent fractions to 3/4 and 4/5

Gre4nikov [31]

3/4 = 6/8 = 9/12
4/5 = 8/10 = 12/15

8 0

3 years ago

Read 2 more answers

(x-2)= - 1/4(x-8) what does x equal?

Alona [7]

Answer:

16/5 or 3 1/5 i think

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

￼ It cost 199 for24 bottles of water what is the unit rate per bottle￼

It cost 199 for24 bottles of water what is the unit rate per bottle