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sweet [91]
2 years ago
6

 It cost 199 for24 bottles of water what is the unit rate per bottle

Mathematics
1 answer:
Lisa [10]2 years ago
8 0

Answer :

the answer is 12

Step :

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110 +0.70x = 50+ 0.90x​
timurjin [86]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x = 300}}}}}

Step-by-step explanation:

\sf{110 + 0.70x = 50 + 0.90x}

Move 0.90x to left hand side and change it's sign

⇒\sf{0.70x - 0.90x + 110 = 50}

Move 110 to right hand side and change it's sign

⇒\sf{0.70x - 0.90x = 50 - 110}

Collect like terms

⇒\sf{ - 0.2x = 50 - 110}

Calculate

⇒\sf{ - 0.2x =  - 60}

Divide both sides of the equation by -0.2

⇒\sf{ \frac{ - 0.2x}{ - 0.2}  =  \frac{ - 60}{ - 0.2} }

Calculate

⇒\sf{x = 300}

Hope I helped!

Best regards!!

5 0
2 years ago
PLA HELP I'LL MARK BRAINLEST
Contact [7]

Answer:

X=55

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
It's summer time, and that means Debbie will be swimming in those awesome hotel pools! The suit she has her eye on was purchased
natima [27]

6.4$

Solution:

Divide 40 and 100(there must always be 100 when solving percentage) then it would be equal to 0.4

after it Multiply it to 16

so we get 6.4.

7 0
2 years ago
Read 2 more answers
What is the y-intercept of this quadratic function f(x) = x^2 + 2x + 3 A. (0,1) B. (0,-1) C. (0,-3) D. (0,3)
Firdavs [7]

Answer:

d=(0,3)

Step-by-step explanation:

8 0
3 years ago
I need help from uh all..​
DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

                         =\frac{1}{2}(\frac{2}{\text{tan}A} ) [Since \text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}]

                         = cot A

Hence right side of the equation is equal to the left side of the equation.

3 0
3 years ago
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