Answer:
a) 2/3
b) 1/3
Step-by-step explanation:
Let X be the random event that measures the time you will have to wait.
Since time is uniformly distributed between 10 and 10:30 in intervals of 1 minute
P(n < X ≤ n+1) = 1/30 for every minute n=0,1,...29.
a)
P( X > 10) = 1 - P(X ≤ 10) = 1 - 10/30 = 2/3
b)
P(10 < X ≤ 20) = (20-10)/30 = 1/3
So probobillity is total sucsesses over total possible or TS/TP so
11/15 so the probobility is 11/15 or 0.73
I think it’s the fourth one!!
10000+4.8%=10480
10480+4.8%=10983.04
10983.04+4.8%=11510.22592
so 3 years
