It results in change of the phase temperature and heat
Telomeres are protective sequences of nucleotides found at the ends of chromosomes,Which become shorter every time a cell divides.
A gradual degeneration of an organism occurs, resulting in ageing.
However, some cells are able to replenish their telomeres using the enzyme telomerase.
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Answer:
Thymidine dimers is likely to be repair as soon as it is originated but if left unrepaired then it causes frame shift mutations.
Explanation:
In case of Bacterium if UV irradiation induces covalent linkage of two thymidine present adjacently to each other or on a single strand to make thymidine dimers.
These either excised via DNA repair enzyme like Endonuclease V and the proof reading activity of DNA polymerase I enzyme help in incorporation of nucleotide by taking the unmutated original strand as a template.
These dimers if not excised before second round of replication than the sequence of newly synthesized strand will be altered. As DNA polymerase III enzyme read thymidine dimers as single thymidine nucleotide and incorporate only 1 adenine in the newly synthesizing complementary strand which results in frame shift mutations
It is the mutation in which reading frame of codons is shifted or altered due to deletion or addition of a single nucleotide.
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
Answer:
The correct answer is option A) "All living organisms use energy".
Explanation:
Even though living being use different strategies to obtain energy, an unifying principle among them is that all living organisms use energy to live. Plant use photosynthesis, which allows them to use sunlight, carbon dioxide and water to obtain energy. This classifies plant as producers, whereas animals that consume plants are primary consumers, animals that consume the animals that consume plants are second consumers, and so on.