The reason why the infant of the mother has this type of abnormality is because of a history that she could have done that could have contributed to this abnormality, what would likely be the cause and the reason it occurred is because the mother has a history of chronic alcohol abuse.<span />
When translated:
In that sense, in a sense,
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
Well everyone moon phase is a phase from where the earth is rotating so it can be determined by the earth rotating
Answer:
III3 will be "pp" lower case p
II2 will be Pp
Explanation:
As we know the trait is caused by dominant alleles. III3 is not affected so she will have two recessice alleles so 2 lower case p.
III2 is affected so the person will have one dominant allele P and one recessive. The dominant is from the father and the recessive is from the mother.
Hope that helps
