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vlada-n [284]
4 years ago
8

Maths question: Expand 3x (2x-1)

Mathematics
1 answer:
scZoUnD [109]4 years ago
3 0
<span>Expand 3x (2x-1)

3x outside must </span>multiply both terms inside the brackets:

= 6x^2 - 3x

Hope it helps
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Express 30 km/h in m/s​
n200080 [17]

Given - 30Km/hr

soution,

we know that

1 km = 1000 m

1 hr = 3600 second

Now

30km/hr = 30×1000÷3600

30Km/hr = 8.34 m/s

Answer - 8.34 m/s

5 0
3 years ago
EMERGENCY I HOPE SOMEONE HELPS ME <br> THANKS
kotykmax [81]
0.28 is the answer unless u put it like 28/100
4 0
3 years ago
Which expression represents the following calculation?
____ [38]

Answer:

(381-22)*16

Step-by-step explanation:

(381-22)*16

3 0
3 years ago
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The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning​ c
uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

 Who had the more convincing victory?

A. Roger​ had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is  D

Step-by-step explanation:

From the question we are told that

  The mean of the current year  is  \mu_c =  186.32 \  minutes

   The standard deviation is  \sigma_c  =  0.305 \  minutes

   The time taken by  the winning car for the current year  is  x =  185.85 \ minutes

  The mean of the previous  year  is  \mu_p =  110.7 \  minutes

   The standard deviation the previous  year  is  \sigma_p  = 0.115  \  minutes

 The time taken by  the winning car for the previous year  is  y =   110.48 \ minutes    

Generally the z-score for current year is mathematically evaluated as

     z_c  =  \frac{x- \mu_c}{\sigma_c }

=>     z_c  =  \frac{ 185.85- 186.32}{0.305 }

=> z_c  = -1.536

Generally the z-score for previous year is mathematically evaluated as

     z_p  =  \frac{y- \mu_p}{\sigma_p }

=>     z_p  =  \frac{ 110.48-110.7}{0.115  }

=> z_p  = -1.913

From the value obtained we see that  z_p  <  z_c , Hence  Karen had a more convincing victory because of the lower z -score.

5 0
3 years ago
PLS HELP ASAP!!!!!<br> (Classify △LMN. Choose 2 answers).
ArbitrLikvidat [17]

Ans : A and F

Step-by-step explanation:

3 0
3 years ago
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