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melomori [17]
3 years ago
6

The textbook procedure is asking you to dissolve 1 g of 3-nitrophthalic acid in hydrazine and only then to add the triethylene g

lycol. In the lab the instructor will tell you to add the triethylene glycol from the very beginning together with hydrazine. What would be a good reason to introduce such change? Select one: a. 3-Nitrophthalic acid is not readily soluble in aqueous hydrazine but it is soluble in organic solvent, triethylene glycol b. Triethylene glycol gives two OH groups to the 3-nitrophthalic acid c. 3-nitrophthalic acid reacts with hydrazine too vigorously if the triethylene glycol is not added d. Hydrazine should react with triethylene glycol prior reacting with 3-nitrophthalic acid
Chemistry
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

The reaction between 3-nitrophthalic acid and hydrazine is highly vigorous. Therefore, the answer is <em>option C</em>.

Explanation:

Triethylene glycol is a high-boiling solvent which necessarily used to contain the synthesis of luminol, which is obtained from the reaction between 3-nitrophthalic acid and aqueous hydrazine. However, this reaction is carried out at a very high temperature, the prior addition of triethylene glycol can allow sufficient reflux for the required completion time without evaporating the solvent fully.

Furthermore, Luminol is an organic compound used to detect metallic ions in Biology. For example, it is used to detect blood traces in forensic investigations.

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trasher [3.6K]

Answer:

0.3?

Explanation:

7 0
3 years ago
HNO3 is an Arrhenius acid and increases the concentration of what??? when added to water.
sineoko [7]
When nitric acid is added to water, the concentration of hydronium ions would increase since the nitric acid dissociates into ions, the hydronium ions and the nitrate ions. Hope this answers the question. Have a nice day. Feel free to ask more questions.
3 0
4 years ago
Consider the reaction and its rate law.
BaLLatris [955]

The order with respect to A is 2

The order with respect to B is 0.

The overall reaction order is 2.

<u>Explanation:</u>

The rate of chemical equation is represented by its rate equation. Here the rate equation of the given chemical reaction is

rate=k[B]^2

Here k represents the rate constant .

Order of the reaction with respect to its individual reactants is represented by the power of the the reactants in the rate equation.

Here the power of the reactant A is 0 and the power of reactant B is 2.

Hence the order with respect to A is 0 and order with respect to B is 2.

The overall order of the reaction is given by the sum of the powers of the reactants in the rate equation.

Hence the total order=2+0=2

4 0
3 years ago
True or false. test tubes, spot and/or well plate will be used to combine substances in bottles and form a reaction. group of an
tresset_1 [31]

Test tubes, spot and/or well plate will be used to combine substances in bottles and form a reaction is referred to a true statement.

<h3>What is a Chemical reaction?</h3>

This is the reaction which involves substances known as reactants combining new substances which are referred to as products. This is usually done in the laboratory and equipment and tools such as test tubes, thermometer etc are used.

Test tubes, spot and/or well plate are often used to combine substances in bottles and form a reaction which must be handled with care to ensure it doesn't spill.

This is therefore the reason why the option true was chosen as the most appropriate choice.

Read more about Chemical reaction here brainly.com/question/11231920

#SPJ1

4 0
2 years ago
What is the reaction for CL^2 + 2 KBr —&gt; 2 KCL+Br^2 of 11 grams of potassium bromide?
mylen [45]

Answer:

All the amounts of reactants and products are:

KBr

          11.0g (given)

          0.0924 mol

Cl₂

           0.0462 mol

           3.28g

KCl

           0.0924 mol

           6.89 g

Br₂

         0.0462 mol

         7.39 g

         

Explanation:

<u>1. Balanced chemical equation (given)</u>

   Cl_2+2KBr\rightarrow 2KCl+Br_2

<u>2. Mole ratios</u>

     \dfrac{1molCl_2}{2molKBr}

      \dfrac{2molKCl}{2molKBr}

     \dfrac{1molBr_2}{2molKBr}

<u />

<u>3. Molar masses</u>

  • Molar mass Cl₂: 70.906g/mol
  • Molar mass KBr: 119.002 g/mol
  • Molar mass KCl: 74.5513 g/mol
  • Molar mass KBr: 159.808 g/mol

<u>4. Convert 11 grams of potassium bromide to moles:</u>

  • #moles = mass in grams / molar mass
  • #mol KBr = 11g / 119.002g/mol = 0.092435mol KBr

<u>5. Use the mole ratios to find the amounts of Cl₂, KCl, and Br₂</u>

a) Cl₂

       \dfrac{1molCl_2}{2molKBr}\times 0.092435molKBr=0.0462molCl_2

        0.0462175molCl_2\times 70.906g/molCl_2=3.28gCl_2

b) KCl

       \dfrac{2molKCl}{2molKBr}\times0.092435molKBr=0.0924molKCl

      0.092435molKCl\times 74.5513g/molKCl=6.89gKCl

c) Br₂

       

         \dfrac{1molBr_2}{2molKBr}\times 0.092435molKBr=0.0462molBr_2

         0.0462175molBr_2\times 159.808g/molBr_2=7.39gBr2

The final calculations are rounded to 3 sginificant figures.

3 0
4 years ago
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