Answer:
Limiting - Na Excess - Cl2
Explanation:
Answer:
Hi, even though this is really not a question or an answer to a question.
Explanation:
Do you know if any of this stuff involves 6th grade?
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You have OH- conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is 4 : 6 = 2:3
So, for 2.3 ✕ 10−6 m OH-
[Cu2+] =

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