Write the formula for the following covalent compounds

Chemistry

1 answer:

IRINA_888 [86]3 years ago

7 0

1.) Carbon Dioxide.

2.) Sulfur Trioxide.

3.) Dinitrogen trioxide.

4.) Dinitrogen pentoxide.

5.) Phosphorus trichloride.

6.) Ammonia.

7.) Sulfur Hexachloride.

8.) Phosphorus Pentoxide.

9.) Carbon Tetrachloride.

10.) Silicon Dioxide.

11.) Carbon Disulfide.

12.) Phosphorus tribromide.

13.) I don't have notes on this one so I don't know.

14.) Aluminum Oxide.

15.) Dichloride Heptoxide. (Not 100% sure if that was a 2 or a 7 at the end.)

<em>Hope this helps and sorry it took so long I had to search through my chemistry notes from awhile ago. But I tried as best I could. :)</em>

You might be interested in

If the solution containing the metal complex ion is made acidic, why will the silver chloride precipitate

Ne4ueva [31]

Answer,

For example, silver ion can be precipitated with hydrochloric acid to yield solid silver chloride. Because many cations will not react with hydrochloric acid in this way, this simple reaction can be used to separate ions that form insoluble chlorides from those that do not.

7 0

3 years ago

A chemist needs to create a series of standard Cu2+(aq)Cu2+(aq) solutions for an absorbance experiment. For the first standard,

lianna [129]

Answer:

The concentration of the Cu²⁺ solution in the 10,0 mL volumetric flask is 5,425×10⁻³ M Cu²⁺

Explanation:

The first dilution from a 2,17M Cu²⁺ solution gives:

2,17 M Cu²⁺ × $\frac{5,00 mL}{500,0 mL}$ = <em>0,0217 M Cu²⁺solution</em>

<em />

The second dilution gives as concentration:

0,0217 M Cu²⁺ × $\frac{25,00 mL}{100,0 mL}$ = 5,425×10⁻³ M Cu²⁺ solution

I hope it helps!

3 0

3 years ago

Read 2 more answers

Which of the following is a reasonable ground-state electron configuration?

qwelly [4]

Following Aufbau rule and Hund principle, the order of filling of the orbitals is this:

$1s^22s^22p^63s^23p^64s^23d^{10}...$

So, the first, second, and fourth option are not correct.

The third option does meet the filling order.

Answer: $1s^22s^22p^63s^23p^64s^23d^1$