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kakasveta [241]

4 years ago

8

Factor 15x^3-6x^2-25x+10 by grouping

1 answer:

Lostsunrise [7]4 years ago

7 0

Answer: (5x-2)(3^2-5)

Step-by-step explanation:

So using the commutative property, we can change the equation 15x^3-6x^2-25x+10 into 15x^3-25x -6x^2+10

Let’s split that into two sections so it’s easier to see:

(15x^3-25x) - (6x^2+10)

Next let’s look at what 15x^3 and -25x have in common. They have 5x in common.

Factoring out 5x, we get this: 5x(3^2-5)

Next let’s look at what -6x^2and 10 have in common. They only have 2 in common, so we factor out 2.

2(-3^2+5) we can write this as -2(3^2-5)

So the end result will be : 5x(3^2-5)-2(3^2-5)

And the complete factorization will be (5x-2)(3^2-5)

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HELP! PLZ I NEED THIS ASAP

harina [27]

Answer:

$2x^{4}+x^{3}-x+2$

Step-by-step explanation:

To find which one is prime, let's try to factor them all. We can use the factoring by grouping method.

$x^{3}+3x^{2}-2x-6$

$x^{3}+3x^{2}$ and $-2x-6$

$x^{2}(x+3)$ and $-2(x+3)$

So this one is not prime, since you can still factor it.

$x^{3}+2x^{2}-3x-6$

$x^{3}+2x^{2}$ and $-3x-6$

$x^{2}(x-2)$ and $3(x-2)$

So this one is not prime, since you can still factor it.

$4x^{4}+4x^{2}-2x-2$

$4x^{4}+4x^{2}$ and $-2x-2$

$4x^{3}(x+1)$ and $-2(x+1)$

So this one is not prime, since you can still factor it.

$2x^{4}+x^{3}-x+2$

$2x^{4}+x^{3}$ and $-x+2$

$x^{3}(2x+1)$ and -x+2 cannot be further factored.

Therefore, $2x^{4}+x^{3}-x+2$ is a prime.

6 0

3 years ago

Which of the following is an example of control?

Sergio039 [100]

dont now sorry i really wont to help

6 0

3 years ago

Susie spent 4 1/4 hours on Monday an 3 5/8 hours on Tuesday working on project. About how long did she spend working on project

adelina 88 [10]

4(1/4)+3(5/8)=
(4+3)+(1/4+5/8)
7+(2/8+5/8)
7+7/8
7 and 7/8

Hope I didn't mess up for your sake

5 0

4 years ago

Read 2 more answers

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Westkost [7]

Answer:

600cm2

Step-by-step explanation:

x3

6 0

3 years ago

Use the initial term and the recursive formula to find an explicit formula for the sequence an. Write your answer in simplest fo

Ipatiy [6.2K]

Answer:

$a_n = -11-14n$

Step-by-step explanation:

Given

$a_1 = -25$

$a_n = a_{n-1}-14$

Required

The explicit formula

First, calculate $a_2$

Set n=2; So:

$a_2 = a_{2-1}-14$

$a_2 = a_{1}-14$

Substitute -25 for $a_1$

$a_2 = -25-14$

$a_2 = -39$

Calculate the common difference (d)

$d = a_2 - a_1$

$d = -39 --25$

$d = -14$

So, the nth term is:

$a_n = a_1 + (n - 1)d$

$a_n = -25+ (n - 1)*-14$

Open bracket

$a_n = -25-14n + 14$

Collect like terms

$a_n = 14-25-14n$

$a_n = -11-14n$

4 0

3 years ago