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san4es73 [151]
3 years ago
15

M

Mathematics
1 answer:
Olegator [25]3 years ago
4 0

Answer:

the answer is B

Step-by-step explanation:

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HELP ONLY ANSWER QUESTION 10. THANKS
swat32
X - 5 = x^2

i) 0 - 5 = -5^2 = 25

ii) 4 - 5 = -1^2 = 1

iii) -4 - 5 = -9^2 = 81
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3 years ago
Simplify.
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Use\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{75}=\sqrt{25\cdot3}=\sqrt{25}\cdot\sqrt3=5\sqrt3\to\boxed{B)}

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(20 POINTS!) Place the circles in order from the circle with the largest area to the circle with the smallest area. 
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Diameter of 16 meters

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You need to sell 250 candy bars at $2 each. If you meet your goal, the total amount of money you will have is measured in the __
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Based on the given details you have given, the total amount of money that you will have will be measured in dollars ($). Since the given value is also in dollars which is $2, therefore, the total amount of money you will have is also in dollars which is 250 x $2 is $500 in total. Hope this answers the question. 
3 0
3 years ago
The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu
Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0
3 years ago
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