3 years ago

Help with part a please

1 answer:

3 0

Use the sum of angles's trigonometric identity formula:
cos(A+B)=(cosAcosB-sinAsinB)
x+y=4cos(t+π/6)+2sint=4(cost*cosπ/6-sint*sinπ/6)+2sint
recall that cosπ//6=√3/2, and sinπ/6=1/2:
4(cost*cosπ/6-sint*sinπ/6)+2sint=4[(√3/2)cost-(1/2)sint]+2sint
simplify:2√3cost-2sint+2sint=2√3cost

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vekshin1

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3 years ago

What is the radical form of each of the given expressions?

earnstyle [38]

Answer:

$6^{\frac{1}{5} }=\sqrt[5]{6}$

$6^{\frac{7}{5} }=\sqrt[5]{6^7}$

$6^{\frac{1}{6} }=\sqrt[6]{6}$

$7^{\frac{1}{2} }=\sqrt[2]{7}$

$7^{\frac{5}{2} }=\sqrt[2]{7^5}$

$6^{\frac{9}{2} }=\sqrt[2]{6^9}$

Step-by-step explanation:

A radical is the root operation for n roots such as square root or cuberoot in the form $\sqrt[n]{x}$ . A fraction exponent $x^{m/n}$ can be converted to the radical form.