Answer:
In the end Joanne had 55 sweets.
Step-by-step explanation:
Let the number of sweets that Xue Ying had be y and let the number of sweets Joanne had be x.
It is given that Xue Ying had 143 more sweets than Joanne. We can write this information as an equation.
y = x + 143.
It is also given that Joanne gave away 22 of her sweets and after that Xue Ying had 6 times as many more sweets. We can write this as an equation.
y = 6(x - 22) = 6x - 132.
Therefore we can equate the two equations and solve for x.
x + 143 = 6x - 132
5x = 275
∴ x = 
sweets.
Therefore in the end Joanne had 55 sweets.
Second option is your answer order from least to greatest
answer: 50/8, 6 2/5, 6.45, 26/4
50/8 = 6.25
6 2/5 = 6.4
26/4 = 6.5
Answer:
a = 
, r = 
Step-by-step explanation:
The sum to infinity of a geometric progression is
; | r | < 1
Thus for first progression
= 6 ( multiply both sides by (1 - r) )
a = 6(1 - r) → (1)
Second progression
= 7 ← multiply both sides by (1 - r² )
2a = 7(1 - r² ) = 7(1 - r)(1 + r) ← difference of squares
2a = 7(1 - r)(1 + r) → (2)
Substitute a = 6(1 - r) into (2)
2(6(1 - r) = 7(1 - r)(1 + r)
12(1 - r) = 7(1 - r)(1 + r) ← divide both sides by (1 - r)
12 = 7(1 + r) = 7 + 7r ( subtract 7 from both sides )
5 = 7r ( divide both sides by 7 )
r =
Substitute this value into (1)
a = 6(1 - ) = 6 × 
=
Two points I can assuming to have integer coordinates (points without decimals in (x, y) ) are (0, 0) and (5, 40)
From this, I can make a safe assumption that y is 8 times the x value.
since x value is money spent on advertising in $1000s', number of vehicles is 80 times of how much money is spent on advertising in $1000.
But, if you want to be fancy (or I guess this is more correct), 8/1000 = 0.08, so for extra dollar spent, 0.08 more vehicles are sold, rounded down.
