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jonny [76]
3 years ago
5

Help please, finals week is upon me​

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0

The circumcenter is found by finding the intersection of at least 2 perpendicular bisector segments.

Find the perpendicular bisector to segment AB. This is the line y = -3.5; the idea is that you find the equation of the horizontal line through the midpoint of AB. The midpoint has a y coordinate of -3.5. This line is shown in red horizontal line in the attached image below.

The midpoint of AC is 2.5, so the perpendicular bisector to AC is x = 2.5 which is shown as the vertical green line in the same diagram.

The red and green lines cross at the location (2.5, -3.5) which is the circumcenter's location. If you were to draw a circle through all three points A, B, & C, then this circle would be centered at (2.5, -3.5)

If point D is the circumcenter, then we know this

AD = BD = CD

basically the distance from the center to any point on the triangle is the same. This is due to the fact that all radii of the same circle are the same length.

<h3>Answer: (2.5, -3.5)</h3>

note: 2.5 in fraction form is 5/2 while -3.5 in fraction form is -7/2

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iVinArrow [24]

Answer:

Let the number of nickels be x

Let the number of pennies be y

Let the number of dimes be z

Now z=x+y

FIrst equation:

z+x+y=16

Subsittue for z:

x+y+x+y=16

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Hope this helps :)

Step-by-step explanation:

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3 years ago
The second sample was the same size as the first, and the proportion of sales identified as organic was 0.4. How does the 95 per
enot [183]

Answer:

The summer interval is wider and has a greater point of estimate  

Step-by-step explanation:

Assuming this problem: "An environmental group wanted to estimate the proportion of fresh produce sales indentified as organic in a grocery store. In the winter, the group obtained a random sample of sales from the store and used the data to construct a 95percent z-interval for a proportion (0.087,0.133). Six months later in the summer, the group obtained a second random sample of sales from the store. The second sample was the same size as the first, and the proportion of sales identified as organic was 0.4. How does the 95 percent z-interval for a proportion constructed from the summer sample compare to the winter interval? "

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

We can find the margin of error from the interval given on this case would be:

ME= \frac{0.133-0.087}{2}=0.023

And the point of estimate for the proportion obtained would be:

\hat p = 0.133-0.023=0.11

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =0.023 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.11(1-0.11)}{(\frac{0.023}{1.96})^2}=710.95  

And rounded up we have that n=711

Now we know that we use the same sample size for the new confidence interval. And replacing into the confidence interval formula we got:

0.4 - 1.96 \sqrt{\frac{0.4(1-0.4)}{711}}=0.364

0.4 + 1.96 \sqrt{\frac{0.4(1-0.4)}{711}}=0.436

And the new 95% confidence interval would be given (0.364;0.436) has a width of 0.436-0.364=0.072. And the width for the previous confidence interval is 0.133-0.087= 0.046. So then the best answer is:

The summer interval is wider and has a greater point of estimate  

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3 years ago
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eimsori [14]
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These are all then translated 3 units left to create the new ordered pairs:

K(-1, -1), G(-1, -4), H(3, -4), J(3, -2)

The two parallel sides are KG and JH.  These were originally CF and DE.
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Answer:

D. 80%

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