By any chance will it be (1,1)
4/3* m^21/12* n^8/3
you need to use enough of laws of indices
Hello there! How are you today?
5a^2 + 2b^3, solve when a = 4 and b = -4
To solve for this, we must replace "a" with 4, and "b" with -4.
I will set it up;
5(4^2) + 2(-4^3)
Simplify the parenthesis (PEMDAS).
5(16) + 2(-64)
Remove the parenthesis by multiplying them by the numbers to the outside of them.
5 x 16 = 80
2 x -64 = -128
We are now left with:
80 - 128
Simplify.
-48 is your final answer.
I hope this helps!
