Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero
x+6=0
x=-6
x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6
use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1
the numbers are -4,-5,-6
Answer:
salmon per pound is $16.68
shrimp per pound is $6.71
Step-by-step explanation:
166.63/10=16.68
16.68*5=83.04
143.86 -83.04=60.46
60.46/9 = 6.71
Answer:
2/3 of the students in a class are girls. if there are 20 boys in the class. then the totoal number of girls is
Answer:
7
Step-by-step explanation:
→ First find the hypotenuse of length 2 and 3
√2² + 3² = √13
→ Use it to find the length of d
√6² + (√13)² = 7
Answer: the maximum distance is and can be found at x =
Let's call:
f(x) = x + 72
g(x) = x²
A point belonging to the line will be L(x, x+72) and a point on the parabola will be P(x, x²). It can be easily seen that in the interval -8 ≤ x ≤ 9 the line is above the parabola (it's enough to graph them or plug in some numbers), therefore their distance at any point will be:
d(x) = f(x) - g(x) = - x² + x + 72
The function d(x) is a parabola that opens downward, therefore the maximum will be the vertex; given a parabola
y(x) = ax² + bx + c
the coordinates of the vertex will be
Therefore:
Hence, the maximum distance is = 72.25 and can be found at x =
Another way to find the maximum is to use calculus to find the first derivative of the distance:
d'(x) = -2x + 1
and set it equal to zero:
-2x + 1 = 0
Since the second derivative:
d"(x) = -2
is negative, the point is a maximum.
Then, substitute this value in the equation for the distance:
<span>Hence, the maximum distance is </span> = 72.25 and can be found at x =