The answer is 25 % hope it helps
Answer: The manager should sell the chair for $1740.
Step-by-step explanation:
45% of 1200 Solve this to find the amount increase
0.45 * 1200 = 540 Now add this amount to find the price.
$1200 + $540 = $1740
or you could do it this way
100% + 45% = 145%
145% of 1200 =?
1.45 * 1200 = 1740
Step-by-step explanation:
Let's call x the lenght and y the height. The perimeter will be:
p = 2x + 2y = 10
When the lenght is halved and the height double we'll have:
p = x + 4y = 14
These 2 equations form a system of equations2 that can be solved and give as result:
y = 3
x = 2
Find the area of the cone:
Area of cone: ⅓r^2h
⅓r^2h
= ⅓(3.5)^2(7)
= ⅓(12.25)(7)
= 1/3(85.75)
= 85.75/3
1/3 cup sloshed out:
(85.75/3 )/3
= 29.9 cubic cm
![\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$3500\\ r=rate\to 6\%\to \frac{6}{100}\to &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\to &4\\ t=years\to &12 \end{cases} \\\\\\ A=3500\left(1+\frac{0.06}{4}\right)^{4\cdot 12}\implies A=3500(1.015)^{48}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%0A%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%0A%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%20%26%5C%243500%5C%5C%0Ar%3Drate%5Cto%206%5C%25%5Cto%20%5Cfrac%7B6%7D%7B100%7D%5Cto%20%260.06%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Bquarterly%2C%20thus%20four%7D%0A%5Cend%7Barray%7D%5Cto%20%264%5C%5C%0At%3Dyears%5Cto%20%2612%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D3500%5Cleft%281%2B%5Cfrac%7B0.06%7D%7B4%7D%5Cright%29%5E%7B4%5Ccdot%2012%7D%5Cimplies%20A%3D3500%281.015%29%5E%7B48%7D)
so, the interest earned then will be A - 3500.