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3 years ago

What is the perimeter, in yards of a rectangular garden that ha as length if 10 yards and a width of 5 yards

Mathematics

1 answer:

kogti [31]3 years ago

7 0

Answer:

100

Step-by-step explanation:

A perimeter is the sum of all of the sides. Since it is a rectangle and it has two pairs of equal sides we can use a simpler formula. The sum of two sides that are next to each other, and then multiplied by two. So we get (10*5)*2. The answer is 50*2=100

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Find the length of the arc.<br> A. 15π mi<br> B. 5400π mi<br> C. 135π mi<br> D. 125π16 mi

weqwewe [10]

Answer:

A. 15π mi

Step-by-step explanation:

First find the circumference

C = 2*pi*r

C = 2 * pi*18

C = 36pi

The arc is 150 degrees

The fraction of the circle is

150/360 = 5/12

Multiply this by the circumference

5/12 * 36 pi

15 pi

7 0

2 years ago

Please don't answer wrong.

Tamiku [17]

Answer:

<u />

<u>Equation of a circle</u>

$(x-a)^2+(y-b)^2=r^2$

where:

(a, b) is the center
r is the radius

Given equation: $x^2+y^2=6.25$

Comparing the given equation with the general equation of a circle, the given equation is a <u>circle</u> with:

center = (0, 0)
radius = $\sqrt{6.25}=2.5$

To draw the circle, place the point of a compass on the origin. Make the width of the compass 2.5 units, then draw a circle about the origin.

Given equation: $x+y=1.5$

Rearrange the given equation to make y the subject: $y=-x+1.5$

Find two points on the line:

$x=-2 \implies -(-2)+1.5=3.5\implies (-2,3.5)$

$x=2 \implies -(2)+1.5\implies-0.5\implies (2,-0.5)$

Plot the found points and draw a straight line through them.

The <u>points of intersection</u> of the circle and the straight line are the solutions to the equation.

To solve this algebraically, substitute $y=-x+1.5$ into the equation of the circle to create a quadratic:

$\implies x^2+(-x+1.5)^2=6.25$

$\implies x^2+x^2-3x+2.25=6.25$

$\implies 2x^2-3x-4=0$

Now use the quadratic formula to solve for x:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

$\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(2)(-4)}}{2(2)}$

$\implies x=\dfrac{3 \pm \sqrt{41}}{4}$

To find the coordinates of the points of intersection, substitute the found values of x into $y=-x+1.5$

$\implies y=-\left(\dfrac{3 + \sqrt{41}}{4}\right)+1.5=\dfrac{3-\sqrt{41}}{4}$

$\implies y=-\left(\dfrac{3 - \sqrt{41}}{4}\right)+1.5=\dfrac{3+\sqrt{41}}{4}$

Therefore, the two points of intersection are:

$\left(\dfrac{3 + \sqrt{41}}{4},\dfrac{3-\sqrt{41}}{4}\right) \textsf{ and }\left(\dfrac{3 - \sqrt{41}}{4},\dfrac{3+\sqrt{41}}{4}\right)$

Or as decimals to 2 d.p.:

(2.35, -0.85) and (-0.85, 2.35)

6 0

2 years ago

PLEASE HELP FOR BRAINLIEST

Schach [20]

Answer:

b=74 degrees c=1O6 degrees

Step-by-step explanation:

B is 74 because its across from the 74 degrees

C is 1O6 degrees because 18Odegrees-74degrees-1O6degress

5 0

3 years ago

Read 2 more answers

Critical points of x+5/x+2>0

Scorpion4ik [409]

Answer:

{-5, -2}

Step-by-step explanation:

In a case like this please use parentheses to remove ambiguities. If I were to take your "x+5/x+2" literally, I'd have to write x plus 5/x plus 2.

I suspect that you actually meant (x + 5) / (x + 2), and will start with that.

First of all, this function is not defined at x = -5 or at x = -2. Thus, -5 and -2 are critical points.

Secondly, there may be one or more critical points beyond this. To find out, we have to differentiate (x+5)/(x+2):

(x + 2)(1) - (x + 5)(1)

f '(x) = ------------------------------

(x + 2)

Here it's clear that x cannot = -2, which would cause division by zero.

Thus, our critical values are {-5, -2}.

8 0

3 years ago

M-6=10<br><br> What does m equal?

Sliva [168]

M is 6 more than 10 so it will be 16

8 0

3 years ago

Read 2 more answers