the length of 3 peices of wire are in the ratio 10:15:8.if the length of the shortest peice of wire is 2.4 find the difference i
1 answer:
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The expression in company B represents that is is in arithmetic progression where first term is 42000 and common difference is 1800 . So we have to use the formula of sum of n terms which is
Where a is the first term, n is the nth term, d is the common difference
On substituting there values,we will get
= 15(84000+52200) = 15*136200 =2043000
And for company A, it is
Difference between them =2043000-2002500= 40500
So the correct option is the second option .
Answer: a)
b) 25165824000
Step-by-step explanation:
The exponential equation for growth is given by :-
, where a= initial value , b =multiplicative growth factor and t = time.
Given : A bacteria culture contains 1500 bacteria initially and doubles every hour.
i.e. a = 1500 and b= 2
Then, the function N that models the number of bacteria after t hours will be :
To find , the number of bacteria after 24 hours , we put t= 24 in above equation , we get
Hence, the number of bacteria after 24 hours is 25165824000.