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rosijanka [135]
3 years ago
15

In Antartica the temperature can change drastically between day and night. At 3:00 pm, the tempature was a chilly 7 degrees Cels

ius. At that time, it began to drop at steady rate of 6 degrees Celsius every hour . What was the temperature at 7:00 pm?
Mathematics
1 answer:
NikAS [45]3 years ago
4 0

Answer:

T = -17\,^{\textdegree}C

Step-by-step explanation:

The temperature at 7:00 pm is:

T = 7\,^{\textdegree}C + \left(-6\,\frac{^{\textdegree}C}{h}  \right)\cdot (4\,h)

T = -17\,^{\textdegree}C

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Which shows the following numbers ordered from greatest to least?
melamori03 [73]

Answer:

D You got it right. 65% 5/8 3/5 0.5

4 0
2 years ago
An object is moving at a speed of 850 miles per hour. Express this speed in meters per minute.
MAVERICK [17]

Answer:

it would be 1385

Step-by-step explanation: because 850 miles per hour converted into meter per min would be 22799.04 meters per sec and then u would Find the number in the whole number place 4 and look one place to the right for the rounding digit on the right side of the decimal point 7. Round up if this number is greater than or equal to 5 and round down if it is less than 5

So the answer is 1385

8 0
3 years ago
Read 2 more answers
How do I find x in this problem?
torisob [31]

Answer:

(6-2)×180 = 720

101+154+72+123+145+x=720

595 + x = 720

x = 720-595

x= 125

5 0
3 years ago
Simplify to create an equivalent expression of<br> 2(−n−3)−7(5+2n)
musickatia [10]
<h3>Answer:   -16n-41</h3>

Work Shown:

2(-n-3) -7(5+2n)

2(-n)+2(-3) - 7(5)-7(2n) ... distribute

-2n - 6 - 35 - 14n

(-2n-14n) + (-6-35)

-16n - 41

6 0
3 years ago
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
3 years ago
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