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3 years ago

Which is the best approximate solution of the system of linear equations y = 1.5x – 1 and y = 1?

Mathematics

2 answers:

Ad libitum [116K]3 years ago

8 0

the correct answer is: B

kolbaska11 [484]3 years ago

7 0

1 = 1.5x - 1
1 + 1 = 1.5x
2 = 1.5x
2/1.5 = x
1.33 = x

solution is : (1.33,1)

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Please help quick please

QveST [7]

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Answer: 183.26

Explanation: see below

I hope this helped!

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3 0

2 years ago

Find x.<br><br>How would you solve this?

Murrr4er [49]

Answer:

x = 100°

Step-by-step explanation:

The measure of a chord- chord angle is half the sum of the arcs intercepted by the angle and its vertical angle, that is

x = $\frac{1}{2}$ (71 + 129)° = 0.5 × 200° = 100°

7 0

2 years ago

Solve the system by elimination. . 4x-9y=-21 , -4x-3y=9

Ivan

(-3, 1)
4x-9y=-21
+-4x-3y=9
-12y= -12
y=1

4x- 9(1)= -21
4x-9=-21
+9 +9
4x= -12
x=-3

7 0

3 years ago

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$

3 0

2 years ago

How do i answer this and how do i find the modal

faltersainse [42]

So firsty up, you need to have equal denominators IN order to do this equation.

1/3 and 5/12..

3x4=12

So the rule when changing denominators, you multiply 4 intop, so it will become 4/12, and 5/12 + 4/12 = 8/12, and,

8/12 + 1/12= 9/12 and 9/12 simplified is 3/4..

So the answer is 3/4.

Hope this helped.

3 0

2 years ago