X=2
f(x)=4^2x-100
f(2)=4^2(2)-100
f(2)=4^4-100
f(2)=256-100
f(2)=156===> Answer
It's y=kx. But 'k' is any constant. So my 'k' can easily be 1/(your k). The key is that when 'x' or 'y' increases by some factor, the other one also increases, by some constant multiple of the same factor. If so, then they're proportional.
Answer:
Part A)
Part B)
Step-by-step explanation:
Par A) Write an equation that relates the distance D this car travels in T hours
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
or
The speed is a proportional relationship between the distance and the time
Let
D ----> the distance in miles
T ----> the time in hours
so
In this problem the constant of proportionality k represent the speed of the car in miles per hour
we have

substitute
Part B) Use the equation to find the distance the car travels between 3:30 p.m. and 5:00 p.m
we know that
The time between 3:30 p.m. and 5:00 p.m is equal to
5:00 p.m-3:30 p.m=1.5 hours
so
For T=1.5 h
substitute in the equation and solve for D
Please check the attached image for the answer. Hope this helps :)
A.) 30+10=40. So, 90-40=50. Your answer is 50 degrees.
B.) 45+4=49. So, 90-49=41. Your answer is 41 degrees.
C.) 8 to the square root of 2+45=56.31. So, 90-56.31=33.69. Your answer is 33.69 or 33.7 if you need to round.
D.) One angle is 30 degrees, and another angle is 60 degrees. Your other angle is 90 degrees.
E.) 60+6=66. 90-66=24. Your answer is 24 degrees.
F.) 45+6=51. 90-51=39. Your answer is 39 degrees.