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Pavlova-9 [17]
2 years ago
6

Many has 48 feet of wood he wants to use all of it to create a border around a garden. The equation 2l+2w=48 can be used to find

the length and width of the garden,where l is the length and w is the width of the garden. If manny makes the garden 15 feet long, how wide should the garden be ?
Mathematics
1 answer:
lord [1]2 years ago
5 0
2L + 2W = 48 

L= 15 feet

substitute the given value to the formula provided.

2(15) + 2W = 48

multiply 2 by 15

30 + 2W = 48

use the subtraction property of equality to cancel the value 30 on the left side. 

30 - 30 + 2W = 48 - 30

cancel 30 on the left side leaving 2W while subtract 30 from 48.

2W = 18

divide both sides to get the value of the width.

2W/2 = 18/2

W = 9ft     this is the final answer.

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A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po
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a. See Attachment 1

b. PT = 12.3\ m

c. HT = 31.1\ m

d. OH = 28.4\ m

Step-by-step explanation:

Calculating PT

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We have to consider angle 50, distance OH and distance OT

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tan50 = \frac{OT}{20}

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Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

tan30 = \frac{OP}{20}

Multiply both sides by 20

20 * tan30 = \frac{OP}{20} * 20

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PT = 12.288

PT = 12.3\ m (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

HT^2 = OT^2 + OH^2

Substitute 20 for OH and OT = 23.836

HT^2 = 20^2 + 23.836^2

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HT^2 = 968.154896

Take Square Root of both sides

HT = \sqrt{968.154896}

HT = 31.1\ m <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

OT * tan50 = {OH

OT * 1.1918 = OH

Substitute OT = 23.836

23.836 * 1.1918 = OH

28.4= OH

OH = 28.4\ m<em> (Approximated)</em>

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