
Factor each of the following differences of two squares and write your answer together with solution.

<h3><u>1. x² - 36</u></h3>

Rewrite
. The difference of squares can be factored using the rule:
.

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<h3><u>2. 49 - x²</u></h3>

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule:
.

Reorder the terms.

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<h3><u>3. 81 - c²</u></h3>

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule:
.

Reorder the terms.

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<h3><u>4</u><u>.</u><u> </u><u>m²</u><u>n</u><u>²</u><u> </u><u>-</u><u> </u><u>1</u></h3>

Rewrite m²n² - 1 as
. The difference of squares can be factored using the rule:
.

Answer:
(a)
(b)
(c)
Step-by-step explanation:
Number of juniors who attended prom,n(J)=28
Number of seniors who attended prom,n(S)=97
- Total of those who attended prom=125
Number of juniors who did not attend prom,n(J')=56
Number of seniors who did not attend prom,n(S')=19
- Total of those who attended prom=75
- Total Number of students=200
(a) P (a junior who did not attend prom)

(b)


(c)P (junior | attended prom)


Answer:
MATH PROBLEM
Step-by-step explanation:
X1= 0, X2= 9
I hope this helps!
Answer:
The amount of interest earned at the end of 14 years would be $672.3486
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
In this problem, we have that:

So

The amount of interest earned at the end of 14 years would be $672.3486