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3 years ago

11

Evaluate the integral using integration by parts with the indicated choices of u and dv. (use c for the constant of integration.

) 2x2 ln(x) dx; u = ln(x), dv = 2x2 dx

1 answer:

ratelena [41]3 years ago

3 0

Try this option (see the attachment).

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The moon takes 28 days to orbit around the earth going at a distance of 2,413,000. How many kilometers does it take for the moon

Mazyrski [523]

Answer:

As per the statement;

The moon takes 28 days to orbit around the earth going at a distance of 2,413,000 km

From the above information,

The ratio between Distance and Days is; $\frac{2413000}{28}$

then,

the distance it takes for the moon to travel one day of its orbit around the earth we have;

$\frac{2413000}{28} \times 1 = \frac{2413000}{28}=86178.57$ km.

Therefore, the distance in kilometer does the moon cover in 1 day is 86178.57 km

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3 years ago

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PLEASE HELP!! I’ll mark you as brainliest if you get it correct !!

Minchanka [31]

The answer is D. A function is to where a line can be drawn upon the y axis and not touch two points.

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Steve Rogers invested $2400 in an account tht pays 4% compounded continuously and how has $3500. How long did it take Steve's mo

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2 years ago

g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa

adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is $\sigma = 0.0133$

Step-by-step explanation:

From the question we are told that

The upper specification is $USL = 1.68 \ mm$

The lower specification is $LSL = 1.52 \ mm$

The sample mean is $\mu = 1.6 \ mm$

The standard deviation is $\sigma = 0.03 \ mm$

Generally the capability index in mathematically represented as

$Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]$

Now what min means is that the value of CPk is the minimum between the value is the bracket

substituting value given in the question

$Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]$

=> $Cpk = min[ 0.88 , 0.88 ]$

So

$Cpk = 0.88$

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2

Now let assuming that

$\frac{\mu - LSL }{ 3 * \sigma } = 2$

So

$\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2$

=> $0.08 = 6 \sigma$

=> $\sigma = 0.0133$

So

$\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }$

=> $2$

Hence

$Cpk = min[ 2, 2 ]$

So

$Cpk = 2$

So $\sigma = 0.0133$ is the value of standard deviation required

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3 years ago

Select the correct answer.

VLD [36.1K]

Answer:

I think the answer is B

Step-by-step explanation:

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