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stellarik [79]
3 years ago
12

Two shapes are similar and their sides have a ratio of 2:9. What is the ratio of the surface areas for

Mathematics
1 answer:
valkas [14]3 years ago
7 0

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] ~\dotfill

\bf s:s\implies 2:9\implies \cfrac{s}{s}\implies \cfrac{2}{9}=\cfrac{\sqrt{Area}}{\sqrt{Area}}\implies \cfrac{2}{9}=\sqrt{\cfrac{Area}{Area}} \\\\\\ \left( \cfrac{2}{9} \right)^2=\cfrac{Area}{Area}\implies \cfrac{2^2}{9^2}=\cfrac{Area}{Area}\implies \cfrac{4}{81}=\cfrac{Area}{Area}

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Answer:

EF =58

Step-by-step explanation:

from the illustration,

EF =DF - DE

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<em>3</em><em>x</em><em> </em><em>+</em><em>1</em><em>0</em><em>=</em><em>9</em><em>x</em><em>-</em><em>3</em><em>9</em><em> </em><em>-</em><em> </em><em>4</em><em>7</em>

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<em>grou</em><em>ping</em><em> like</em><em> </em><em>ter</em><em>ms</em>

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<em>x  =  \frac{96}{6}</em>

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EF= 3(16)+10

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Answer:

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Step-by-step explanation:

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Mary's original garden was in the shape of a square. She has decided to double the area of her garden. So the new area of Mary's garden will be 2 times the area of original garden.

We can represent this information in an equation as:

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\text{Area of Mary's new garden}=2(8\text{ ft})^{2}

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\text{Area of Mary's new garden}=128\text{ ft}^{2}

Therefore, the area of Mary's new garden will be 128 square feet.

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