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3 years ago

14

riverside elementary school is holding a school wide election to choose a school color. five-eighths of the votes were for blue

five-ninth of the remaining votes were for green

1 answer:

katen-ka-za [31]3 years ago

8 0

Blue won that election

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An author receives a contract from a publisher, according to which she is to be paid a fixed sum of $20,000 plus $3.50 for each

Schach [20]

Answer:

The mean of the total payments she will receive is $79,500.

The standard deviation of the total payments she will receive is $14,000.

Step-by-step explanation:

Given : An author receives a contract from a publisher, according to which she is to be paid a fixed sum of $20,000 plus $3.50 for each copy of her book sold. The author judges that her uncertainty about total sales of the book can be represented by a random variable with a mean of 17,000 and a standard deviation of 4,000 books.

To find : The mean and standard deviation of the total payments she will receive ?

Solution :

Let 'x' represent total sales of the book.

Let 'y' represent the payment to the author.

According to question,

The mean of the total payments she will receive is given by,

$\mu_y=20,000+3.50\mu_x$

Where, $\mu_x=17,000$

Substitute in the equation,

$\mu_y=20000+3.50\times 17000$

$\mu_y=20000+59500$

$\mu_y=79500$

The mean of the total payments she will receive is $79,500.

The standard deviation of the total payments she will receive is given by,

$\sigma_y=|3.50|\sigma_x$

Where, $\sigma_x=4,000$

Substitute in the equation,

$\sigma_y=|3.50|\times 4000$

$\sigma_y=14000$

The standard deviation of the total payments she will receive is $14,000.

7 0

3 years ago

HELP ME PLEASEEE THANK YOUU<br><br><br> yes or no?

sertanlavr [38]

No as it doesn’t go vertically through 1/3 on x axis

3 0

2 years ago

Read 2 more answers

The vertical asymptote of the function f(x) = 3 log(x + 3)

ipn [44]

A function has a vertical asymptote where it is not defined, and the logarithm is defined only if its argument is strictly positive: it has a vertical asymptote if its argument is zero, and is not defined if its argument is negative.

So, you have a vertical asymptote where

$x+3=0 \iff x=-3$

4 0

3 years ago

I need help with this question. Write the equation in standard form. Identify A,B, and C.

frutty [35]

$\frac{5}{2}x-9=8y\\
\frac{5}{2}x-8y=9\\\\
A=\frac{5}{2}\\
B=-8\\
C=9$

6 0

3 years ago

Which of the following correctly describes the domain of the function shown

labwork [276]

Option D:

$\{x: x \neq 1\}$ is the domain of the function.

Solution:

Given function is

$$r(x)=\frac{2 x}{x-1}$

<u>To find the domain of the function:</u>

Option A: $\{x: x \neq 0\}$

Substitute x = 0 in r(x).

$$r(0)=\frac{2 \times 0}{0-1}=0$

If x = 0, then r(0) = 0

So that x ≠ 0 is false.

So, $\{x: x \neq 0\}$ is not the domain of the function.

Option B: $\{x: x \neq \pm 1\}$

Substitute x = –1 in r(x).

$$r(-1)=\frac{2 \times (-1)}{-1-1}=1$

If x = –1, then r(–1) = 1

So that x = ± 1 is false.

So, $\{x: x \neq \pm 1\}$ is not the domain of the function.

Option C: $\{x: \text { all real numbers }\}$

Substitute x = 1 in r(x).

$$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}$

It is indeterminate.

So, all real numbers are not the domain of the function.

Option D: $\{x: x \neq 1\}$

Substitute x = 1 in r(x).

$$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}$

It is indeterminate.

So, $\{x: x \neq 1\}$ is the domain of the function.

4 0

3 years ago